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382 LES PORTIQUES

20                                                L = H =10                                                    20                                                 L =10 ; H = 5
     W                                            h1 h2                                                             W                                             h1 h2

18                                                                                                             18

16                                                             W+1     H  + 4(I1    1           L2             16                                              W  W            +1          H    + 4(I1     1              L2
                                                            W       k  L          I2 + 2L                      14                                                                k         L            I2 + 2L
                                                                                           H)H2                                                                                                                      H)H2
14
                                                               =W  +   1H  +            1              L                                                          =W                       +1   H  +  ((Ω1      1              L
                                               k =1                    kL                                                                                                                    k  L
                                           2                                  4((Ω1  Ω2 )(L  H)+2) H                                                                                                        Ω 2 )(L  H ) + 8) H
12 4
                                10 86                                                                          12
                                 ∞
                                                                                                                                                         k =1
10                                                                                                             10 2

                                                                                                    Z =0.75                                        4
                                                                                                                                          ∞ 1086

 8                                                                                                              8                                                                                                              Z =0.75
7.5 k = 1                                                                                                      7.5
                                                                                                                                                                                                                              Z =0.375
                                   2                                                                                   ∞  10       4    2     k =1                                                                             Z =0.25
                      108 6 4                                                                                                8

   6∞                                                                                                             6             6

           ∞ 108 6 4 2          k =1

  4                                                                                                 Z =0.375                 ∞ 10 8 6 4 2 k = 1
3.75                                                                                                Z =0.25      4
                                                                                                               3.75
 2.5
  2                                                                                                             2.5
                                                                                                                 2

                                                                                                          LL

                                                                                                                          HH
   00

      0 1 2 3 4 5 6 7 8 9 10                                                                                         0 1 2 3 4 5 6 7 8 9 10

9                                           Figure 2.12.3.                                                     9                                               Figure 2.12.4.

     Ω1σ                                              L = H =10                                                     Ω1σ                                                      L =10; H = 5
                                                      h1 h2                                                                                                                  h1 h2
      p1L                                                                                                            p1L

88

77

6                                                                                                              6

                                                                                                    Z =0.75

                                 ∞                                                                                                                k =1
                                10 8 6 4 2
5                                                                                                              5                               2
                                                                                                                                10 86 4
                                            k =1                                                                                                                                                                              Z =0.75

                                                                                                                          ∞

4                                                                                                              4

3 k =1                                                                                              Z =0.375   3                           k =1
                                                                                                      Z =0.25       ∞                   2
                 2                                                                                                                                                                                                            Z =0.375
                                                                                                                            64                                                                                                 Z =0.25
           86 4                                                                                                           108
           10

2∞                        k =1                                                                                 2                                    k=1

                       2                                                                                                      10 8 6 4     2
           10 86 4                                                                                                     ∞

      ∞

11

                                                                                                                        LL
                                                                                                                        HH

00
   0 1 2 3 4 5 6 7 8 9 10 0 1 2 3 4 5 6 7 8 9 10

                                            Figure 2.12.5.                                                                                                     Figure 2.12.6.
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